2u^2-5u+37=(u-3)

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Solution for 2u^2-5u+37=(u-3) equation: 



2u^2-5u+37=(u-3)

We move all terms to the left:

2u^2-5u+37-((u-3))=0



We calculate terms in parentheses: -((u-3)), so:

(u-3)

We get rid of parentheses

u-3

Back to the equation:

-(u-3)



We get rid of parentheses

2u^2-5u-u+3+37=0

We add all the numbers together, and all the variables

2u^2-6u+40=0

a = 2; b = -6; c = +40;
Δ = b2-4ac
Δ = -62-4·2·40
Δ = -284
Delta is less than zero, so there is no solution for the equation

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